-(x^2+x+10)+18=1

Solution for -(x^2+x+10)+18=1 equation:

-(x^2+x+10)+18=1

We move all terms to the left:

-(x^2+x+10)+18-(1)=0

We add all the numbers together, and all the variables

-(x^2+x+10)+17=0

We get rid of parentheses

-x^2-x-10+17=0

We add all the numbers together, and all the variables

-1x^2-1x+7=0

a = -1; b = -1; c = +7;
Δ = b2-4ac
Δ = -12-4·(-1)·7
Δ = 29
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{29}}{2*-1}=\frac{1-\sqrt{29}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{29}}{2*-1}=\frac{1+\sqrt{29}}{-2}
$